Parsing an XML from Online in Android

Posted by Unknown Senin, 04 Maret 2013 0 komentar
Create a fresh project and name it ParseXMLDemo
Then in the ParseXMLDemo.java file copy this code
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import java.util.ArrayList;
import java.util.HashMap;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.NodeList;
import android.app.ListActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.AdapterView;
import android.widget.ListAdapter;
import android.widget.ListView;
import android.widget.SimpleAdapter;
import android.widget.Toast;
import android.widget.AdapterView.OnItemClickListener;

public class ParseXMLDemo extends ListActivity {
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);

ArrayList<String> mylist = new ArrayList<String>();
String xml = ParseXMLMethods.getXML();
Document doc = ParseXMLMethods.XMLfromString(xml);
int numResults = ParseXMLMethods.numResults(doc);

if((numResults <= 0)){
Toast.makeText(ParseXMLDemo.this, "There is no data in the xml file", Toast.LENGTH_LONG).show();
finish();
}

NodeList children = doc.getElementsByTagName("os");
for (int i = 0; i < children.getLength(); i++)
{
HashMap<string string=""> map =new HashMap<string string="">();
Element e = (Element)children.item(i);
map.put("id", ParseXMLMethods.getValue(e, "id"));
map.put("name", ParseXMLMethods.getValue(e, "name"));
map.put("site", ParseXMLMethods.getValue(e, "site"));
mylist.add(map);
}
ListAdapter adapter = new SimpleAdapter(this,mylist ,R .layout.list_layout,
new String[] { "name", "site" },
new int[] { R.id.title, R.id.subtitle});

setListAdapter(adapter);


final ListView lv = getListView();
lv.setOnItemClickListener(new OnItemClickListener() {
public void onItemClick(AdapterView parent, View view, int position, long id) {
@SuppressWarnings("unchecked")
HashMap<String, String> o = (HashMap<String, String>) lv.getItemAtPosition(position);
Toast.makeText(ParseXMLDemo.this,o.get("name"), Toast.LENGTH_LONG).show();
}
});
} }

Now create another java file inside the src folder and name it ParseXMLMethods.java and copy this contents into it.
import java.io.IOException;
import java.io.StringReader;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;

public class ParseXMLMethods {

public final static Document XMLfromString(String xml){

Document doc = null;
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
try {
DocumentBuilder db = dbf.newDocumentBuilder();
InputSource is = new InputSource();
is.setCharacterStream(new StringReader(xml));
doc = db.parse(is);
}
catch (ParserConfigurationException e) {
System.out.println("XML parse error: " + e.getMessage());
return null;
}
catch (SAXException e) {
System.out.println("Wrong XML file structure: " +e.getMessage());
return null;
}
catch (IOException e) {
System.out.println("I/O exeption: " +e.getMessage());
return null;
}
return doc;
}
public final static String getElementValue( Node elem ) {
Node kid;
if( elem != null){
if (elem.hasChildNodes()){
for( kid = elem.getFirstChild(); kid != null;kid = kid.getNextSibling() ){
if( kid.getNodeType() == Node.TEXT_NODE ){
return kid.getNodeValue();
}
}
}
}
return "";
}
public static String getXML(){
String line = null;
try {
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost("http://new ABC.com/xml/test.xml");
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
line = EntityUtils.toString(httpEntity);
} catch (Exception e) {
line = "Internet Connection Error >> " + e.getMessage();
}
return line;
}

public static int numResults(Document doc)
{
Node results = doc.getDocumentElement();
int res = -1;
try
{
res = Integer.valueOf(results.getAttributes()
.getNamedItem("count").getNodeValue());
}catch(Exception e ){
res = -1;
}
return res;
}

public static String getValue(Element item, String str)
{
NodeList n = item.getElementsByTagName(str);
return ParseXMLMethods.getElementValue(n.item(0));
}
}
in main.xml:
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent">

<ListView
android:id="@id/android:list"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:layout_weight="1"
android:background="#FF0000"
android:drawSelectorOnTop="false"/>
</LinearLayout>
list_layout.xml:
< ?xml version="1.0" encoding="utf-8"?> 
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:padding="7dp">
<TextView
android:id="@+id/title"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:textAppearance="?android:attr/textAppearanceMedium"
android:padding="2dp"
android:textSize="20dp"
android:textStyle="bold"/>
<TextView
android:id="@+id/subtitle"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:padding="2dp"
android:textSize="14dp"
android:textColor="#000000"/>
</LinearLayout>
Strings.xml:
<?xml version="1.0" encoding="utf-8"?> 
<resources>
<string name="hello"> Hello World, ParseXMLDemo!</string>
<string name="app_name"> ParseXMLDemo New ABC.com</string>
</resources>
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Judul: Parsing an XML from Online in Android
Ditulis oleh Unknown
Rating Blog 5 dari 5
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